[jboss-user] [EJB 3.0] - Re: check if a lazy property is loaded

[vboerchers]

Thanks for the answer ablevine! It works exactly as you wrote. I've implemented some helper methods that does everything we need:

  |   public static String getObjectDescription(Object o)
  |   {
  |       if (o instanceof HibernateProxy)
  |       {
  |           LazyInitializer initializer = ((HibernateProxy) o)
  |                .getHibernateLazyInitializer();
  |           return initializer.getEntityName()
  |                + "#" + initializer.getIdentifier();
  |       }
  |       return o.toString();
  |   }
  | 
This one is also nice:

  |   public static boolean canBeUsed(Object o)
  |   {
  |       if (o instanceof HibernateProxy)
  |       {
  |           LazyInitializer initializer = ((HibernateProxy) o)
  |               .getHibernateLazyInitializer();
  |           // if already initialized - use it!
  |           if ( ! initializer.isUninitialized())
  |               return true;
  |           // if the session still works - use it!
  |           return initializer.getSession() != null
  |               && initializer.getSession().isOpen();
  |       }
  |       return true;
  |   }
  | 
The ultimative cure for LazyInitializationExceptions is a combination of canBeUsed() and a dedicated service that does something like that:

  |   mEm.find(Class.forName(initializer.getEntityName())
  |      , initializer.getIdentifier());
  | 

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