[rules-users] newbie question on "when" condition syntax

[Michael Anstis]

Glad my hasty original reply has been ripped apart ;-)

Goes to show that everybody has something new to learn.

Thanks to everyone for the corrections (and simpler, correct, solution!).

Mike


On 02/05/2008, mashup <richard.bremner.nb at googlemail.com> wrote:
>
>
> Ahhh I wondered about that, thanks. Again, now I see it, it makes complete
> sense. This drools stuff is actually pretty damn good!
>
> Richard
>
> Chris Woodrow wrote:
> >
> > You're right, if you want to do this with 2 facts, you'll need to do :
> >
> >   $test : Test( $y : y )
> >   Test(
> > this == $test,
> > x == ($y + 1) )
> >
> > Chris
> >
> > 2008/5/2 Raffi Khatchadourian <khatchad at cse.ohio-state.edu>:
> >
> >> On Fri  2.May'08 at 10:05:20 +0100, Anstis, Michael (M.) wrote:
> >>
> >> > The "when" section matches fact (object) patterns, so your
> requirement
> >> > could be written as:-
> >> >
> >> > when there is a Test Fact 'A' and another Test Fact 'B' where "the
> 'x'
> >> > property of 'A'" equals "the 'y' property of fact 'B' plus 1"
> then.....
> >> >
> >> > This would become:-
> >> >
> >> > rule "Rule 1"
> >> > when
> >> >   Test( $y : y )
> >> >   Test( x == ($y + 1) )
> >> >
> >>
> >> Actually, please correct me if I am mistaken, but is this condition
> >> correct? I believe that the original question is that for a single
> >> instance of class Test t, fire the rule when t.x == t.y + 1 (where 't'
> >> refers to the *same* instance of class Test). I believe the rule above
> >> would match any instance of class Test whose x value is equal to the
> >> value of the instance field y from *any* instance of class Test plus 1.
> >> Does that make sense?
> >> _______________________________________________
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> >> rules-users at lists.jboss.org
> >> https://lists.jboss.org/mailman/listinfo/rules-users
> >>
> >
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> >
> >
>
> --
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>
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