[rules-users] forall over a collection
Wolfgang Laun
wolfgang.laun at gmail.com
Fri Mar 20 04:08:05 EDT 2009
You don't need forall to solve your problem. The following rule prints all
patient names which don't have problem 4711; omitting the 'not' prints
those suffering from Colognitis.
rule lookJoe
when
$patient: Patient()
not ( Problem( code == "4711" ) from $patient.problemList )
then
System.out.println( $patient.getName() );
end
'not' implies quantification (or exhaustive search over the domain).
Without 'not' also searches all Problem entries of the current Patient
so it would fire again if the patient has a problem stored more than
once.
-W
2009/3/20 howard goldberg <goldberg.howard at gmail.com>
> Trying to check whether a patient has a particular problem on their problem
> list:
>
> when
>
> $patient : Patient()
> forall ( Problem( code != "195967001") from $patient.problemList)
>
> but I get the following parsing error--
>
> [29,41]: [ERR 101] Line 29:41 mismatched input 'FROM' expecting ')' in rule
> "Dumb no asthma Rule"
> [29,66]: [ERR 101] Line 29:66 mismatched input ')' expecting '(' in rule
> "Dumb no asthma Rule" in pattern $patient.problemList
>
> What is the correct way to check for this condition?
>
> Thanks,
> Howard
>
>
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>
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