Each (not <i>the</i>) Recommendation with the maximum recommValue can be found using<br><br> $recMax: Recommendation( slot == 1, $recommValue: recommValue)<br> not Recommendation( slot == 1, recommValue > $recommValue )<br>
<br>with $recMax being bound to one of the Recommendations with the maximum,<br>and the maximum value being bound to $recommValue.<br><br>-W<br><br><div class="gmail_quote">On 24 November 2012 13:18, raffi <span dir="ltr"><<a href="mailto:christian.koehler@s2008.tu-chemnitz.de" target="_blank">christian.koehler@s2008.tu-chemnitz.de</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Hello,<br>
<br>
I have a problem with using the /from accumulate/ statement. It is because<br>
I'd like to optmize my code a liitle bit. There are two rules that I like to<br>
merge.<br>
<br>
/query "max recomm value for slot 1"<br>
accumulate (Recommendation(slot == 1, $recomm_value : recommValue),<br>
max : max($recomm_value))<br>
end/<br>
<br>
and<br>
<br>
/query "recomms for slot 1"<br>
recomm : Recommendation(slot == 1)<br>
end/<br>
<br>
So with the first rule I get the maximum of the variable recommValue. The<br>
second rule is for searching exactly this Recommendation-fact with this<br>
value. Now I tried to merge them in the following way:<br>
/<br>
query "recomm for slot 1"<br>
$recomm : Recommendation() from<br>
accumulate(Recommendation(<br>
slot == 1, $recomm_value : recommValue),<br>
max($recomm_value)<br>
)<br>
end/<br>
<br>
But the returned value always is a double one. Is it because of the usage of<br>
the maximum function? Is it possible to solve this problem with only one<br>
query (getting that Recommendation-fact with the highest recommValue)?<br>
<br>
Regards...<br>
<br>
<br>
<br>
--<br>
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</blockquote></div><br>