You can use the "resolveType" method to resolve the FQN:

JavaClassSource source = Roaster
.parse(JavaClassSource.class,
"import foo.bar.Talk;"
+ ""
+ "public class TalkService extends CrudService<Talk, Long> {}");

String superType = source.getSuperType();
String firstType = Types.splitGenerics(superType)[0];
String resolvedType = source.resolveType(firstType);
System.out.println(resolvedType);// Returns "foo.bar.Talk"
Best Regards,


George Gastaldi

Principal Software Engineer

ggastald@redhat.com    M: +55-47-99711-1000



On Sat, Mar 9, 2019 at 5:01 PM Rafael Pestano <rmpestano@gmail.com> wrote:
Hi guys,

I have the following class:

public class TalkService extends CrudService<Talk, Long> ...


and I need to get the JavaClassSource of the first superClass type argment (Talk).
 
The only way I've found was to get the type argument name and then find the entity by looking at the imports but I wonder if there's a simpler way:

JavaClassSource service = Roaster.parse....
String entityName = service.getSuperType().substring(service.getSuperType().indexOf("<")+1,service.getSuperType().indexOf(","));

Optional<Import> entityImport = service.getImports().stream().filter(i -> i.getQualifiedName().endsWith(entityName))
            .findFirst();

  String entityQualifiedName = entityImport.get().getQualifiedName();
 String sourceFolder = sourceFacet.getSourceDirectory().getFullyQualifiedName();

            JavaClassSource entity = Roaster.parse(JavaClassSource.class, new File(sourceFolder + "/" + entityQualifiedName.replace(".", "/") + ".java"));




 
--
Att,

Rafael M. Pestano

Desenvolvedor Java Cia. de Processamento de Dados do Rio Grande do Sul
http://rpestano.wordpress.com/
@realpestano
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