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Re: Cron expression in jBPM5 gives exception

created by onkar ruikar in jBPM - View the full discussion

Used following rule to run the process:

import org.drools.runtime.process.ProcessContext

rule "everyDay" ruleflow-group "Hello"

    timer (cron:0 0 23 ? * FRI)
when

then
    System.out.println(new java.util.Date());
    kcontext.getKnowledgeRuntime().startProcess("sample");
end

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