The above code is working fine. I have done this reading http://stackoverflow.com/questions/2637017/how-do-i-do-a-multipart-form-file-upload-with-jax- rs I am able to upload the files.I am unable to get the filename uploaded.In Jersey we can easily get the Content-Disposition using @FormDataParam("fileName") FormDataContentDisposition fcdsFile
fcdsFile.getFileName().
Please any body help me to get the fileName from Content-Dsipositon of file uploaded using rest easy