You can simplify the query:

query "sortedItems"
 TreeMap( $values: values() )
       from accumulate( $f: Fact(),
                  init( TreeMap map = new TreeMap(); ),
                  action( map.put(factKey($f), $f); ),
                  reverse( map.remove(factKey($f)); ),
                  result( map ) )
end

-W


On 28 November 2011 10:58, Syargey <Syargey@tut.by> wrote:
I don't want to sort facts outside of drools rules. The sorting is part of
business requirements. My opinion is that is not a good thing to keep parts
of business logic in different places.

I spent some time to figure out how it is possible to sort a collection of
facts and here is my solution:
---------------------------
function String factKey(Fact f)
{
   return String.format( "%010d~~%s~~%s", f.getRank(), f.getName(),
f.getValue() );
}

query sortFactsQuery
   $factsMap: HashMap()
       from accumulate( $f: Fact(),
                    init( HashMap map = new HashMap(); ),
                  action( map.put(factKey($f), $f); ),
                  reverse( map.remove(factKey($f)); ),
                  result( map ) )
   $sortedKeyList: TreeSet()
       from collect( String() from $factsMap.keySet() )
   $sortedFacts: List()
       from accumulate( $key: String() from $sortedKeyList,
                                       collectList( $factsMap.get( $key ) ) )
end
-----------------------

--
View this message in context: http://drools.46999.n3.nabble.com/facts-custom-sort-tp3538410p3541805.html
Sent from the Drools: User forum mailing list archive at Nabble.com.
_______________________________________________
rules-users mailing list
rules-users@lists.jboss.org
https://lists.jboss.org/mailman/listinfo/rules-users