hi,

I'm going to convert a PackageDescr object which has the rules to XML file.I'm trying to convert it into xml using dump method of XmlDumper class. The problem with that is while the rest of the code is fine i cannot get the lhs part. There is no method in fact as far as i know to actually specify the lhs. The setLhs method does not help in this regard. I tried to construct all the parameters ususally specified in the lhs like the ColumnDescr object and FieldBinding object but there is no way to bind these to the PackageDescr object.
So the lhs is coming out as null while the rest of the code is fine ...even the rhs..

I am attaching the code and the output again. please go through and advise.

thanking you,

Niloy Debnath
student(comp sc & engg)

OUTPUT OF TEST2 :

<?xml version="1.0" encoding="UTF-8"?>

<package name="org.drools.examples"

xmlns="http://drools.org/drools-3.0"

xmlns:xs="http://www.w3.org/2001/XMLSchema-instance"

xs:schemaLocation="http://drools.org/drools-3.0 drools-3.0.xsd">

<import name="org.drools.examples.Hell.Message" />

<rule name="Hell">

<lhs>null

null

</lhs><rhs>System.out.println( message );m.setMessage( "Goodbye cruel world " );m.setStatus( Message.GOODBYE );modify( m );</rhs>

</rule><rule name="Good">

<rule-attribute name="activation-group" value="dekhajak" />

<lhs><rule-attribute name="activation-group" value="dekhajak" />

<rule-attribute name="activation-group" value="dekhajak" />

</lhs><rhs>System.out.println( message ); m.setMessage( message );</rhs>

</rule>

</package>

no visitor implementation for : class org.drools.lang.descr.PatternDescr : org.drools.lang.descr.PatternDescr@14318bb

no visitor implementation for : class org.drools.lang.descr.PatternDescr : org.drools.lang.descr.PatternDescr@14318bb

no visitor implementation for : class org.drools.lang.descr.PatternDescr : org.drools.lang.descr.PatternDescr@14318bb

no visitor implementation for : class org.drools.lang.descr.PatternDescr : org.drools.lang.descr.PatternDescr@14318bb

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