On 01/30/2013 09:33 AM, Bruno Oliveira wrote:
So if I'm a bank where the user account is logged in, this user has just forgot to 'logout'. Another person using his computer can just bypass the login, because the session still exists?
Banks get over this by frequently being proactive using Javascript. If the user has been idle for a minute, they give out a warning and if there is no response, they log out the user.


Another scenario, I'm at the same network of John, running my whatever-sniffer, then is just a matter of grab the current session ID and login? Am I wrong? Because If understood correctly, after user login, even if I invoke this method for a second time, what really matters is the session ID.
https/ssl should be mandatory for all critical web applications.  Just have a HTTP Header agent installed for your browser. Your passwords are in the clear in the http header agent if you do not use https.

I'm confused. 



-- 
"The measure of a man is what he does with power" - Plato
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@abstractj
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Volenti Nihil Difficile



On Wednesday, January 30, 2013 at 1:17 PM, Anil Saldhana wrote:


> On 01/29/2013 08:08 PM, Douglas Campos wrote:

> > On Tue, Jan 29, 2013 at 05:19:23PM -0600, Anil Saldhana wrote:

> > > Shane,
> > > this is not a bug rather a feature request.

> > 
> > 
> > it's a bug

> > > Aerogear has the following sequence:
> > > 
> > > credential.setCredential(x);
> > > identity.login();
> > > credential.setCredential(y);
> > > identity.login();
> > > 
> > > Aerogear wants PicketLink to reauthenticate during the second login()
> > > call. Currently
> > > it will not because the first login() established a User instance and
> > > subsequent login()
> > > calls will just bypass the auth process.

> > 
> > 
> > If my API doesn't do the login process on the login() call, am I not
> > failing with the "least surprise principle"? If it doesn't do all the
> > login procedure when called, better rename it then: mayLogin(),
> > loginWithCaching() or anything like this.

> 
> 
> Your usage:
> 
> User user = null;
> AuthenticationResult result = identity.login();
> if(result == AuthenticationResult.SUCCESS){
> user = identity.getUser();
> } else {
> throw new RuntimeException("Authentication Failed");
> }
> 
> //Now identity has an user
> //Irrespective of what you want to put in credential, you are 
> authenticated already until you logout
> result = identity.login();
> //result is always SUCCESS.
> 

> > 
> > IMO, this is not only wrong, but I think it can be used as a potential
> > attack vector.

> 
> 
> How?

> > 
> > -- qmx

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