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https://issues.jboss.org/browse/TEIIDDES-2038?page=com.atlassian.jira.plu...
]
Steven Hawkins commented on TEIIDDES-2038:
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That is the incorrect runtime type, unless the meaning in this file
is the xsd/xml representation.
I should add that from a runtime perspective, we ignore the runtime type set by designer
and override it with the one from the datatypes.dat mapping. So if you need to leave this
as string for whatever reason that would be fine.
I can then move this issue back to Teiid if all we need to do is use the uuid from above.
While importing from Deployed BQT2 VDB, JDBC type of 0 and type name
NULL was returned for column with design-time type varbinary
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Key: TEIIDDES-2038
URL:
https://issues.jboss.org/browse/TEIIDDES-2038
Project: Teiid Designer
Issue Type: Bug
Reporter: Barry LaFond
Attachments: TEIID_2829_project.zip
1) Open attached project in Designer
2) Deploy the BQT2.vdb
3) Create another project
4) Import the VDB metadata via JDBC Importer into your second project (will end up being
a read-only VDB source model)
5) On *finish* you'll get an exception when processing the type_varbinary column
because the type returned is "0" and type name of "null"
{code}
java.lang.IllegalArgumentException: Expected argument to be non-null but got null
at org.teiid.core.designer.util.CoreArgCheck.isNotNull(CoreArgCheck.java:142)
at org.teiid.core.designer.util.CoreArgCheck.isNotNull(CoreArgCheck.java:128)
at
org.teiid.designer.sdt.types.BuiltInTypesManager.getBuiltInDatatype(BuiltInTypesManager.java:477)
at
org.teiid.designer.sdt.types.WorkspaceDatatypeManager.getBuiltInDatatype(WorkspaceDatatypeManager.java:94)
at
org.teiid.designer.jdbc.relational.impl.RelationalModelProcessorImpl.findType(RelationalModelProcessorImpl.java:1450)
at
org.teiid.designer.jdbc.relational.impl.RelationalModelProcessorImpl.setColumnInfo(RelationalModelProcessorImpl.java:1321)
{code}
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