If you just want access to the raw data you have a 2 options:

HttpServerExchange.getRequestChannel()
HttpServerExchange.getInputStream() (exchange should have startBlocking called, and you need to dispatch to a worker thread so as not to block an IO thread)

If you want access to parsed form/multipart data then you can use io.undertow.server.handlers.form.EagerFormParsingHandler, and the use exchange.gutAttachment(FormDataParser.FORM_DATA) to get access to the parsed data.

Stuart

----- Original Message -----
> From: "Mike Stefaniak" <mstefaniak@choicestream.com>
> To: undertow-dev@lists.jboss.org
> Sent: Friday, 2 January, 2015 10:32:35 AM
> Subject: [undertow-dev] HttpServerExchange post data
>
> I can't figure out how to get the content of post data
>
> My server start
>
> Undertow.builder()
> .addHttpListener(8080, "0.0.0.0")
> .setHandler(Handlers.routing().post("/bid", new BidHandler()))
> .build()
> .start();
>
> And the handler class
>
> public final class BidHandler implements HttpHandler {
>
> @Override
> public void handleRequest(final HttpServerExchange exchange) throws Exception
> {
> ........
> }
> }
>
>
> If I make a curl request like so
>
> curl -H "Content-Type: application/json" -X POST -i -d '{"some": "value"}'
> http://127.0.0.1:8080/bid
>
> It gets to the handler, but I can't figure out to access the post data from
> the request
>
> Thanks
>
>
>
>

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