[hibernate-issues] [Hibernate-JIRA] Commented: (HHH-5735) Usage Path.type() in expressions throws java.lang.IllegalArgumentException
Jaroslaw Lewandowski (JIRA)
noreply at atlassian.com
Tue Nov 16 07:29:16 EST 2010
[ http://opensource.atlassian.com/projects/hibernate/browse/HHH-5735?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=39129#action_39129 ]
Jaroslaw Lewandowski commented on HHH-5735:
-------------------------------------------
I have to mention that this test passes in reference implementation of JPA 2.0 - EclipseLink (this one actually works there ;)
> Usage Path.type() in expressions throws java.lang.IllegalArgumentException
> ---------------------------------------------------------------------------
>
> Key: HHH-5735
> URL: http://opensource.atlassian.com/projects/hibernate/browse/HHH-5735
> Project: Hibernate Core
> Issue Type: Bug
> Components: query-criteria
> Affects Versions: 3.6.0, 3.6.1
> Reporter: Jaroslaw Lewandowski
> Priority: Blocker
> Attachments: InheritanceTest.tgz
>
>
> It is not possible to filter entities using Path.type() in Criteria Query API. Using type() in expressions throws an exception:
> Unexpected call on EntityTypeExpression#render
> java.lang.IllegalArgumentException: Unexpected call on EntityTypeExpression#render
> at org.hibernate.ejb.criteria.expression.PathTypeExpression.render( at org.hibernate.ejb.criteria.expression.PathTypeExpression.render(PathTypeExpression.java:48PathTypeExpression.java:48)
> )
> at org.hibernate.ejb.criteria.predicate.ComparisonPredicate.render(ComparisonPredicate.java:173)
> at org.hibernate.ejb.criteria.QueryStructure.render(QueryStructure.java:258)
> at org.hibernate.ejb.criteria.CriteriaQueryImpl.render(CriteriaQueryImpl.java:340)
> at org.hibernate.ejb.criteria.CriteriaQueryCompiler.compile(CriteriaQueryCompiler.java:223)
> at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:441)
> at foo.InheritanceTest.critQryTest(InheritanceTest.java:55)
> Test case is attached and it's similar to an example from JPA 2.0 specification - chapter 6.5.7 Example 2:
> CriteriaQuery<Employee> q = cb.createQuery(Employee.class);
> Root<Employee> emp = q.from(Employee.class);
> q.select(emp)
> .where(cb.notEqual(emp.type(), Exempt.class));
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