[hibernate-issues] [Hibernate-JIRA] Commented: (HHH-5291) Hibernate generates several join clauses for same table
Claudio Tagliola (JIRA)
noreply at atlassian.com
Tue Mar 20 05:27:50 EDT 2012
[ https://hibernate.onjira.com/browse/HHH-5291?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=46028#comment-46028 ]
Claudio Tagliola commented on HHH-5291:
---------------------------------------
We have this issue with 3.6.9. Did you ever find a workaround?
> Hibernate generates several join clauses for same table
> -------------------------------------------------------
>
> Key: HHH-5291
> URL: https://hibernate.onjira.com/browse/HHH-5291
> Project: Hibernate ORM
> Issue Type: Bug
> Components: core
> Affects Versions: 3.5.2
> Environment: Hibernate 3.5.2
> Reporter: Igor Nikolaev
>
> Suppose you've got a mapping:
> <class name="Class" table="TABLE1" dynamic-update="true">
> <id name="id" type="int">
> <column name="ID" />
> <generator class="assigned" />
> </id>
>
> <discriminator column="CLASS_TYPE"/>
> <property name="property1" type="string" column="PROPERTY1" update="false" insert="false"/>
>
> <join table="TABLE2" optional="true">
> <key column="ID" not-null="false"/>
> <property name="property2" column="PROPERTY2"/>
> </join>
>
> <subclass name="Subclass" discriminator-value="SUBCLASS">
> <join table="TABLE2">
> <key column="swift_id"/>
> <property name="property3" column="PROPERTY3"/>
> </join>
> </subclass>
> </class>
> As you can notice, we join the same table in subclass.
> Expected result is that Hibernat generates a query like this one:
> select
> this_.ID,
> this_.PROPERTY1,
> this_1_.PROPERTY2,
> this_1_.PROPERTY3
> from
> TABLE1 this_
> left inner join
> TABLE2 this_1_
> on this_.ID=this_1_.ID
> Instead, Hibernate joins TABLE2 twice and generates the following query:
> select
> this_.ID,
> this_.PROPERTY1,
> this_1_.PROPERTY2,
> this_2_.PROPERTY3
> from
> TABLE1 this_
> left inner join
> TABLE2 this_1_
> on this_.ID=this_1_.ID
> left outer join
> TABLE2 this_2_
> on this_.ID=this_2_.ID
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