[jboss-jira] [JBoss JIRA] Updated: (JBRULES-2745) Problems in the use of escapes in the "matches" operator

[Alessandro Lazarotti (JIRA)]

     [ https://jira.jboss.org/browse/JBRULES-2745?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel ]

Alessandro Lazarotti updated JBRULES-2745:
------------------------------------------

    Attachment: drools-simple-regex.zip


> Problems in the use of escapes in the "matches" operator
> --------------------------------------------------------
>
>                 Key: JBRULES-2745
>                 URL: https://jira.jboss.org/browse/JBRULES-2745
>             Project: Drools
>          Issue Type: Bug
>      Security Level: Public(Everyone can see) 
>    Affects Versions: 5.1.1.FINAL
>            Reporter: Alessandro Lazarotti
>            Assignee: Mark Proctor
>         Attachments: drools-simple-regex.zip
>
>
> According to official documentation, it is not necessary to use escapes:
> "In contrast to Java, escapes are not needed within regular expressions written as string literals." (a note in topic 4.8.2.1.5.)
> But it is not true. Actually even the example of the documentation does not work if you do not use escape:
> //type is a String
> Cheese( type matches "(Buffalo)?\S*Mozarella" )
> ... should be changed to:
> //type is a String
> Cheese( type matches "(Buffalo)?\\S*Mozarella" )
> Curiously, if you have a attribute of the attribute which matches a regex, you shouldn't use escapes:
> //type is "complex type" and value is a String
> Cheese( type.value matches "(Buffalo)?\S*Mozarella" )
> ... it's work!
> That said, a workaround to work with simple String attributes, you should use "toString":
> //type is "String" 
> Cheese( type.toString matches "(Buffalo)?\S*Mozarella")

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