Connecting two server channels efficiently

[Eric Bouer]

On Thursday 29 April 2010 01:17:58 Johnny Luong wrote:
> beric wrote:
> > Hello list of a very nice project.
> > I'm trying to bridge two listening sockets so that any data on each of
> > them will reach the other. the UNIX way is: "cat fifo | nc -l -p 3344 |
> > nc -l -p 3355 > fifo" Now help me figure the Netty way :)
> > 
> > My current way of doing that is by having 2 ServerBootstrap, while one of
> > them(foo) has a SimpleChannelUpstreamHandler that has access to the
> > pipeline of the other ServerBootstrap(bar) by holding a ChannelPiple
> > member.
> > 
> > Then, in channelOpen I'm trying to add an OutboundHAndler(from
> > HexDumpProxy) to the channelpipeline of bar.
> > 
> > It looks like this:
> >  @Override
> >  
> >     public void channelOpen(ChannelHandlerContext ctx, ChannelStateEvent
> >     e)
> > 
> > throws Exception {
> > 
> >     //Suspend incoming traffic
> >     final Channel inboundChannel = e.getChannel();
> >     inboundChannel.setReadable(false);
> >     this.sb2piChannelPipeline.addLast("handler-sb2", new
> > 
> > OutboundHandler(e.getChannel()));
> > 
> >     }
> > 
> > However I get a IllegalArgumentException : Duplicate handler name.
> > I guess I did something wrong. I would like to know why, or any (probably
> > better) alternative implementation of what I'm trying to do here.
> > Thanks.
> 
> Would it make more sense just to have a ChannelGroup (add each new
> incoming channel to the set) for each listener and then within each
> handler, have it write to the appropriate channelgroup what that
> individual channel received?
> 
> Best,
> Johnny
> 
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I'm not sure I'm right but if I'll write to that ChannelGroup you mentioned 
I'll get an "echo" effect when  data arrives . I don't want that.
Am I right ?