[rules-dev] ruleFlowId as a dynamic way

[mjido]

Hi,
But I don't like to use startProcess several times.
I shouldn't invoke startprocess every time when i add another process.
I have ruleFlow files as input and i want to invoke startProcess one time.
I don't like to pass id by explicit form.
I need a generic code for this.
Thanks

Kris Verlaenen wrote:
> 
> Each process defines its own id.  If you look in the xml, the process
> element has an id attribute.  In the editor, click on the background of
> your process and you will also see the id property in the properties view.
> 
> So you should give each of your processes a new id. Then you can easily
> start each of those processes:
> 
>   startProcess("MyFirstProcess");
>   startProcess("MySecondProcess");
> 
> Does that make sense?
> 
> Kris
> 
> Quoting mjido <m.benlachgar at netfective.ma>:
> 
>> 
>> Hello,
>> I think i'm not very clear.
>> I have multiple ruleFlow files and i want to execute them with
>> startProcess(id).
>> But how i can associate each ruleFlow with his id.
>> Is there a way to get id process from ruleFlow file?
>> 
>> mjido wrote:
>> > 
>> > Hi,
>> > I use workingMemory.startProcess(Id_process) to execute multiple
>> rulflow
>> > files.
>> > So i want to pass Id_proccess as a dynamic value.
>> > Is there any way to make this? 
>> > Any helps will be very appreciated.
>> > 
>> 
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