[rules-users] Writing complicated rules - consecutive number problem

[Swindells, Thomas]

Something like this may work?

p : Person() //for any person
exists( Person(age < p.age)) //who has someone younger than them
not (Person(age == p.age-1)) //there must be someone 1 year younger than them.
then
//there is a gap
end

if you only want it to fire once then you may need an extra exists around it or something.

Thomas

> -----Original Message-----
> From: rules-users-bounces at lists.jboss.org [mailto:rules-users-
> bounces at lists.jboss.org] On Behalf Of LCode
> Sent: 05 November 2011 15:16
> To: rules-users at lists.jboss.org
> Subject: [rules-users] Writing complicated rules - consecutive number
> problem
>
> I am trying to write a rather complicated rule via the guided rule editor and I
> wonder if it is indeed possible.
>
> The following is a simplified explanation of my scenario:
>
>
> A 'person' has a numerical property 'age'
>
>
> In a hypothetical world the following is allowed because the ages of the
> people are consecutive:
>
> Person A age = 24
>
> Person B age = 25
>
> Person C age = 26     OK
>
> Person D age = 27
>
>
> However I would like to write a rule that fires if the ages are not consecutive,
> something like this:
>
> Person A age = 24
>
> Person B age = 25
>
> Person C age = 29     NOT OK
>
> Person D age = 27
>
>
>
> I am starting with 'From collect all people [p]'.
>
>
> Any thoughts, comments or similar experiences much apprieciated as I am
> pulling my hair out!
> Jen
>
> --
> View this message in context: http://drools.46999.n3.nabble.com/Writing-
> complicated-rules-consecutive-number-problem-tp3482704p3482704.html
> Sent from the Drools: User forum mailing list archive at Nabble.com.
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> rules-users at lists.jboss.org
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