[rules-users] Test for element in an arraylist

[Wolfgang Laun]

You cannot use the operator "contains" in an eval(), where a simple
Java expression
must be written:

   eval(odmList.contains($a1) && odmList.contains($a2))

But I agree with Jeremy: the original rule is rather unlikely, as it
would fire for
a single ODMAnswer being contained in the odmList, or two different ODMAnswers
being contained in the list, and then again for the same two ODMAnswers being
contained in the list...

Basics, study the basics...
-W


On 16 January 2013 18:03, Bojan Janisch
<bojan.janisch at scai.fraunhofer.de> wrote:
> Nah thats not gonna work, because I'm using
> an ArrayList as a global variable. I'm adding
> and removing ODMAnswers in it and always want to
> check if there are 2 ODMAnswers in it, to remove
> them and generate a new one.
>
> Of course I differ them in their properties, just
> wanted to keep the problem simple and understandable.
>
> Do you got another option than creating a local
> $list variable?
>
> ----- Ursprüngliche Mail -----
> Von: "Jeremy Ary" <jeremy.ary at gmail.com>
> An: "Rules Users List" <rules-users at lists.jboss.org>
> Gesendet: Mittwoch, 16. Januar 2013 17:54:32
> Betreff: Re: [rules-users] Test for element in an arraylist
>
>
>
> I should note that hopefully you can limit this to something like $list : ODAList ( ) (a specific extends type of list where you could specify some criteria to be more specific with) or can assure that you only have one List in play at that time, or you're going to spend some execution going through every List in memory to check for these occurrences.
>
>
> Jeremy
>
>
>
> On Wed, Jan 16, 2013 at 10:50 AM, Jeremy Ary < jeremy.ary at gmail.com > wrote:
>
>
>
> Argh...Sorry, wrong key too early...here's the full changes:
>
>
> rule "Combine ODMAnswers"
>
> when
> $list : List( )
> $a1:ODMAnswer( some check ) from $list $a2:ODMAnswer( assuming something making this one different than $a1 ) from $list
> then
> $list.add( new ODMAnswer( ) );
> $list.remove($a1);
> $list.remove($a2);
> end
>
>
>
>
>
>
> On Wed, Jan 16, 2013 at 10:47 AM, Jeremy Ary < jeremy.ary at gmail.com > wrote:
>
>
>
>
> Try this;
>
>
> rule "Combine ODMAnswers"
>
> when
> $a1:ODMAnswer( some check )
> $a2:ODMAnswer( assuming something making this one different than $a1 )
>
>
>
> eval(odmList contains $a1 && odmList contains $a2)
> then
> ODMAnswer answer = new ODMAnswer( );
> odmList.add(answer);
> odmList.remove($a1);
> odmList.remove($a2);
> end
>
>
>
>
>
> On Wed, Jan 16, 2013 at 10:41 AM, Bojan Janisch < bojan.janisch at scai.fraunhofer.de > wrote:
>
>
>
> rule "Combine ODMAnswers"
>
> when
> $a1:ODMAnswer( )
> $a2:ODMAnswer( )
>
> eval(odmList contains $a1 && odmList contains $a2)
> then
> ODMAnswer answer = new ODMAnswer( );
> odmList.add(answer);
> odmList.remove($a1);
> odmList.remove($a2);
> end
>
>
>
>
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