[rules-users] Re: accumulate over multiple types

[Geoffrey De Smet]

Edson Tirelli wrote:
> 
>     Geoffrey,
> 
>     I don't think you need multiple patterns for this specific use case:
> 
> rule "multipleQueensHorizontal"
> when
>      Queen($id : id, $y : y)
>      Number( $multipleQueensHorizontal : intValue )
>      from accumulate( $q : Queen(id > $id, y == $y), count($q) );
> then
>     // do something
> end

This would result in the number of (higher id) queens which are at the 
same horizontal position for a certain queen.
But I need the sum of that for all queens.

For example for these rows:
AB_D_F
__C___
____E_
This would give me:
A: 3
B: 2
C: 0
D: 1
E: 0
F: 0
That's all correct, but I need the sum of that:
multipleQueensHorizontal: 6

After that I 'd like to use that for a sum of multipleQueensHorizontal, 
multipleQueensDiagonalUp and multipleQueensDiagonalDown (vertical is 
always 0 due to my moves and start position) which gives me the score 
(the only thing that I really need).

I could of course do a logicalAssert of a number per queen and then 
accumulate those, kinda what I did with the 
WorkaroundMultiplePatternAccumulate object.

But it looks like accumulate is improving my performance already, great 
work :) Or could it be because I am now using rules with assertLogical() 
instead of query's?

> 
>    Am I misunderstanding your use case?

> 
>    []s
>    Edson

With kind regards,
Geoffrey De Smet
> 
> 
> 2007/7/28, Geoffrey De Smet <ge0ffrey.spam at gmail.com 
> <mailto:ge0ffrey.spam at gmail.com>>:
> 
>     I 'd like to get the number of queens which have the same y.
> 
>     I used to do this with a query:
>         query "multipleQueensHorizontal"
>             Queen($id : id, $y : y);
>             Queen(id > $id, y == $y);
>         end
>     And then ask the size() of it.
> 
>     But now I should be able to do this with the accumulate function:
>          $multipleQueensHorizontal : Integer()
>          from accumulate(
>              $q1 : Queen($id : id, $y : y);
>              Queen(id > $id, y == $y);
>            , count($q1)
>          );
> 
>     However, I get a parsing error on it:
>        Caused by: org.drools.rule.InvalidRulePackage: [31,37]: unknown:31:37
>     Unexpected token ';'[33,6]: unknown:33:6 mismatched token:
>     [@123,814:814=',',<12>,33:6]; expecting type THEN
> 
>     Apparently the ; in of "$q1 : Queen($id : id, $y : y);" is inacceptable?
> 
>     --
>     With kind regards,
>     Geoffrey De Smet
> 
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> 
> 
> 
> -- 
>   Edson Tirelli
>   Software Engineer - JBoss Rules Core Developer
>   Office: +55 11 3529-6000
>   Mobile: +55 11 9287-5646
>   JBoss, a division of Red Hat @ www.jboss.com <http://www.jboss.com>
> 
> 
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