ChannelBuffer to HttpRequest - using HttpRequestDecoder

[Renjith T]

Ok - got this.  Having an implementation like this - helped got past the 
default visibility of 'decode' :


   new MyDecoder().decode(ctx, e.getChannel(), (ChannelBuffer) 
e.getMessage() );

   static class MyDecoder extends HttpRequestDecoder {

       public Object decode(ChannelHandlerContext ctx,
           Channel channel,
           ChannelBuffer buffer)
               throws Exception {
         return super.decode(ctx, channel, buffer,
             HttpMessageDecoder.State.READ_INITIAL);
       }
     }


This worked great, but I wanted to reuse the ChannelBuffer after 
decoding as well ( since after this the stream returns empty ).

So , used the .copy() method of ChannelBuffer to take care of the same.

   new MyDecoder().decode(ctx, e.getChannel(), (ChannelBuffer) 
e.getMessage()*.copy()* );

That worked fine.

But - is that an equivalent of a clear() method to force release the 
contents though ?




On 08/04/2011 01:06 AM, Renjith T wrote:
> I am working on a handler ( from SimpleChannelUpstreamHandler), that 
> gives the message in messageRecieved as a ChannelBuffer .
>
>     public void messageReceived(ChannelHandlerContext ctx, final 
> MessageEvent e)
>             throws Exception {
>          final ChannelBuffer request  = (ChannelBuffer) e.getMessage();
>           ... // do something
>
>     }
>
>
> I would like to convert this ChannelBuffer to a HttpRequest, through 
> some means, if possible.
>
> (   pipeline.addLast("decoder", new HttpRequestDecoder()); , in the 
> pipeline factory does not work since I need the raw ChannelBuffer as 
> mentioned above , for some other downstream processing as well).
>
> How can I achieve the above ?
>
>
>
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