[hibernate-issues] [Hibernate-JIRA] Commented: (JPA-24) java.sql.SQLException: Invalid argument in JDBC call: parameter index out of range when trying to persist an entity mapped with insertable = false, updatable = false on @Column

java.sql.SQLException: Invalid argument in JDBC call: parameter index out of range when trying to persist an entity mapped with insertable = false, updatable = false on @Column -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- Key: JPA-24 URL: https://hibernate.onjira.com/browse/JPA-24 Project: Java Persistence API Issue Type: Bug Environment: Hibernate 4.0.0.CR4, HSQLDB 2.0, MySQL 5.1 Reporter: Karsten Wutzke Attachments: hib-readonly-col.zip The following mappings are all JPA 1.0 compatible (no derived identifiers): {code:Company.java} @Entity @Table(name = "Companies") public class Company { @Id @Column private Integer id; @Column private String name; ... } {code} {code:PQ.java} @Entity @Table(name = "PQs") public class PQ implements Serializable { @Id @Column private Integer id; @Column private String name; ... } {code} {code:Partnership.java} @Entity @Table(name = "Partnerships") @IdClass(value = PartnershipId.class) public class Partnership implements Serializable { @Id @Column(name = "pq_id", insertable = false, updatable = false) private Integer pqId; @Id @Column(name = "company_id", insertable = false, updatable = false) private Integer companyId; @Column(name = "ordinal_nbr") private Integer ordinalNbr; @ManyToOne @JoinColumn(name = "pq_id", referencedColumnName = "id") private PQ pq; @ManyToOne @JoinColumn(name = "company_id", referencedColumnName = "id") private Company company; ... } {code} {code:PartnershipId.java} public class PartnershipId implements Serializable { private Integer pqId; private Integer companyId; public PartnershipId() { } public PartnershipId(Integer pqId, Integer companyId) { this.pqId = pqId; this.companyId = companyId; } ... } {code} Note, the insertable = false, updatable = false on @JoinColumn relationships. Running the following test code {code:Main.java} public class Main { private static String PERSISTENCE_UNIT_NAME = "standalonePu"; private static EntityManagerFactory emf; private static EntityManager em; private static EntityTransaction trans; public static void main(String[] args) { setUp(PERSISTENCE_UNIT_NAME); trans.begin(); PQ detachedPq = new PQ(1, "Test PQ"); Company detachedCompany = new Company(1, "Test Company"); PQ pq = em.merge(detachedPq); Company company = em.merge(detachedCompany); Partnership detachedPartnership = new Partnership(1, 1, 1); detachedPartnership.setPQ(pq); detachedPartnership.setCompany(company); Partnership partnership = em.merge(detachedPartnership); partnership = em.find(Partnership.class, new PartnershipId(1, 1)); System.out.println("Persistent partnership = (" + partnership.getPQId() + ", " + partnership.getCompanyId() + ", " + partnership.getOrdinalNbr() + ")"); trans.commit(); close(); } private static void setUp(String puName) { emf = Persistence.createEntityManagerFactory(puName); em = emf.createEntityManager(); trans = em.getTransaction(); } private static void close() { em.close(); emf.close(); } } {code} fails with a really strange exception: ERROR: Invalid argument in JDBC call: parameter index out of range: 4 Exception in thread "main" javax.persistence.RollbackException: Error while committing the transaction at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:90) at main.Main.main(Main.java:44) Caused by: javax.persistence.PersistenceException: org.hibernate.exception.GenericJDBCException: Invalid argument in JDBC call: parameter index out of range: 4 at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1347) at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1280) at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:78) ... 1 more Caused by: org.hibernate.exception.GenericJDBCException: Invalid argument in JDBC call: parameter index out of range: 4 at org.hibernate.exception.internal.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:148) at org.hibernate.exception.internal.SQLStateConverter.convert(SQLStateConverter.java:136) at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124) at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:109) at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:131) at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:80) at $Proxy12.setInt(Unknown Source) at org.hibernate.type.descriptor.sql.IntegerTypeDescriptor$1.doBind(IntegerTypeDescriptor.java:57) at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:82) at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:305) at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:300) at org.hibernate.type.ComponentType.nullSafeSet(ComponentType.java:358) at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2599) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2836) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3276) at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:80) at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:273) at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:265) at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:186) at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:344) at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:50) at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1084) at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:319) at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:100) at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:173) at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:73) ... 1 more Caused by: java.sql.SQLException: Invalid argument in JDBC call: parameter index out of range: 4 at org.hsqldb.jdbc.Util.sqlException(Unknown Source) at org.hsqldb.jdbc.Util.sqlException(Unknown Source) at org.hsqldb.jdbc.Util.sqlException(Unknown Source) at org.hsqldb.jdbc.Util.outOfRangeArgument(Unknown Source) at org.hsqldb.jdbc.JDBCPreparedStatement.checkSetParameterIndex(Unknown Source) at org.hsqldb.jdbc.JDBCPreparedStatement.setInt(Unknown Source) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:601) at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:124) ... 22 more Caused by: org.hsqldb.HsqlException: Invalid argument in JDBC call: parameter index out of range: 4 at org.hsqldb.error.Error.error(Unknown Source) ... 31 more I've also tested this with MySQL with the same JDBC exception. Note the workaround to resolve this is to put `..., insertable = false, updatable = false` onto the relationships' `@JoinColumn`s (but it's not really what I want). Please fix.