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http://opensource.atlassian.com/projects/hibernate/browse/HHH-1819?page=all ]
Steve Ebersole updated HHH-1819:
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Fix Version: 3.3
Assign To: Steve Ebersole
Priority: Minor (was: Critical)
initially scheduling this for 3.3 because my gut tells me this will need the SQL rendering
changes targetted for 3.3 to resolve this issue. This may get moved up to 3.2.3 or 3.2.4
if that is found to not be the case.
Invalid SQL generated for mapping with property-ref
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Key: HHH-1819
URL:
http://opensource.atlassian.com/projects/hibernate/browse/HHH-1819
Project: Hibernate3
Type: Bug
Components: query-hql
Versions: 3.1.3
Environment: Oracle 8.1.7
Reporter: Jakub Mendys
Assignee: Steve Ebersole
Priority: Minor
Fix For: 3.3
Consider mappings:
<class name="MedDRATerm" table="MBROW_MEDDRA_TERMS"
mutable="false"
batch-size="50">
<cache usage="read-only" region="dictionary" />
<id name="medDRATermId" type="long"
column="TERM_ID">
<generator class="assigned" />
</id>
<map name="termNames" table="MBROW_TERM_NAMES"
lazy="true"
batch-size="50">
<cache usage="read-only" region="dictionary" />
<key column="MEDDRA_CODE" property-ref="medDRACode" />
<index column="LANGUAGE_ID"
type="com.roche.dss.meddra.dao.type.LanguageType" />
<element column="NAME" type="string" />
</map>
<property name="medDRACode" column="MEDDRA_CODE"
type="com.roche.dss.meddra.dao.type.MedDRACodeType" />
</class>
<class name="MedDRATermInstance" table="MBROW_MEDDRA_TREES"
mutable="false">
<cache usage="read-only" region="dictionary" />
<id name="medDRATermInstanceId" type="long"
column="NODE_ID">
<generator class="assigned" />
</id>
<many-to-one name="medDRATerm" class="MedDRATerm"
column="TERM_ID" fetch="join" not-null="true"
insert="false"
update="false" />
</class>
and a HQL query:
from MedDRATermInstance i where i.medDRATermInstanceId is not null and
i.medDRATerm.termNames[1] like 'headache'
Having this Hibernate will generate following SQL:
SELECT ...
FROM orcl_gthes.mbrow_meddra_trees meddraterm0_,
orcl_gthes.mbrow_term_names termnames2_
WHERE meddraterm1_.meddra_code = termnames2_.meddra_code
AND termnames2_.language_id = 1
AND meddraterm0_.term_id = meddraterm1_.term_id
AND (termnames2_.NAME LIKE 'headache')
Please note that WHERE clause refers to alias meddraterm1_ which is not mentioned in FROM
section!!!!
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