Daniel Novo ( https://hibernate.atlassian.net/secure/ViewProfile.jspa?accountId=5ae986b... ) *updated* an issue Hibernate ORM ( https://hibernate.atlassian.net/browse/HHH?atlOrigin=eyJpIjoiY2I4ZGNiODVl... ) / Bug ( https://hibernate.atlassian.net/browse/HHH-16622?atlOrigin=eyJpIjoiY2I4ZG... ) HHH-16622 ( https://hibernate.atlassian.net/browse/HHH-16622?atlOrigin=eyJpIjoiY2I4ZG... ) Criteria API - Already registered a copy ( https://hibernate.atlassian.net/browse/HHH-16622?atlOrigin=eyJpIjoiY2I4ZG... ) Change By: Daniel Novo ( https://hibernate.atlassian.net/secure/ViewProfile.jspa?accountId=5ae986b... ) With Criteria API, reusing Predicates with subqueries we are getting this error: {noformat}Already registered a copy: org.hibernate.query.sqm.tree.select.SqmSubQuery@4416e18d{noformat} Without subqueries, we are getting other error {noformat}org.hibernate.sql.ast.SqlTreeCreationException: Could not locate TableGroup{noformat} Sample: {noformat}CriteriaBuilder cb = entityManager.getCriteriaBuilder(); CriteriaQuery<MyEntity> cq = cb.createQuery(MyEntity.class); Root<MyEntity> root = cq.from(MyEntity.class); List<Predicate> predicates = getPredicates(cb,cq, root, "1"); cq.select(root).where(predicates.toArray(Predicate[]::new)); TypedQuery<MyEntity> q = entityManager.createQuery(cq); long count = count(entityManager, predicates);{noformat} Same code in hibernate 5 works fine. Test case: [https://github.com/DanielNovo/hibernate-test-case-templates/commit/e6b5f4...] ( https://hibernate.atlassian.net/browse/HHH-16622#add-comment?atlOrigin=ey... ) Add Comment ( https://hibernate.atlassian.net/browse/HHH-16622#add-comment?atlOrigin=ey... ) Get Jira notifications on your phone! Download the Jira Cloud app for Android ( https://play.google.com/store/apps/details?id=com.atlassian.android.jira.... ) or iOS ( https://itunes.apple.com/app/apple-store/id1006972087?pt=696495&ct=Em... ) This message was sent by Atlassian Jira (v1001.0.0-SNAPSHOT#100225- sha1:11e4e77 )