If you just want access to the raw data you have a 2 options:
HttpServerExchange.getRequestChannel()
HttpServerExchange.getInputStream() (exchange should have startBlocking called, and you
need to dispatch to a worker thread so as not to block an IO thread)
If you want access to parsed form/multipart data then you can use
io.undertow.server.handlers.form.EagerFormParsingHandler, and the use
exchange.gutAttachment(FormDataParser.FORM_DATA) to get access to the parsed data.
Stuart
----- Original Message -----
From: "Mike Stefaniak" <mstefaniak(a)choicestream.com>
To: undertow-dev(a)lists.jboss.org
Sent: Friday, 2 January, 2015 10:32:35 AM
Subject: [undertow-dev] HttpServerExchange post data
I can't figure out how to get the content of post data
My server start
Undertow.builder()
.addHttpListener(8080, "0.0.0.0")
.setHandler(Handlers.routing().post("/bid", new BidHandler()))
.build()
.start();
And the handler class
public final class BidHandler implements HttpHandler {
@Override
public void handleRequest(final HttpServerExchange exchange) throws Exception
{
........
}
}
If I make a curl request like so
curl -H "Content-Type: application/json" -X POST -i -d '{"some":
"value"}'
http://127.0.0.1:8080/bid
It gets to the handler, but I can't figure out to access the post data from
the request
Thanks
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