> Look in hibernate tools code generation code on how to do this. > > It is a component not a persistentclass. > > I don't have the source just available here, but something like > Cfg2Java.getJavaType(property) should > give you a good idea. > Thanks a lot! > What is it for ? I am working under the following issues: JBIDE-1422 Hibernate Configurations view: Open Source File / Mapping File/ Mapping diagram actions are disabled for joined-subclass JBIDE-1412 Mapping diagram: improve "Open Source/Mapping" actions and uder improvement of context menu at all. I've almost finished it, but I can't open Sourca and Mapping file without enough information about the objects(it is concerning the Component Properties). I've made some scrinshots to show how it works now. Dima > > -max > > >> Hi All! >> >> I have the following mapping structure in my hbm.xml file: >> >> <class name="Person" >> discriminator-value="P"> >> ... <component name="address"> >> <property name="street"/> >> <property name="zip"/> >> <property name="country"/> >> </component> >> ... >> >> In Java code I get object of the type >> org.hibernate.mapping.Property. For example it is "zip" property. >> >> The question is: how can I know that my Property object is property >> of "address" Subclass ("address" component). >> >> Property.getPersistanceClass() returns null. >> > > >