[jboss-user] [EJB 3.0] - Make a default interceptor the inner interceptor

Given <ejb-jar xmlns="http://java.sun.com/xml/ns/javaee" | xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" | xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/ejb-jar_3_0.xsd" | version="3.0"> | | <interceptors> | <interceptor> | <interceptor-class>org.jboss.seam.ejb.SeamInterceptor</interceptor-class> | </interceptor> | </interceptors> | | <assembly-descriptor> | <interceptor-binding> | <ejb-name>*</ejb-name> | <interceptor-class>org.jboss.seam.ejb.SeamInterceptor</interceptor-class> | </interceptor-binding> | </assembly-descriptor> | | </ejb-jar> how can I make sure that SeamInterceptor is always the inner most interceptor in the stack? I see that the EJB3 spec allows me specify a total order (if I know the interceptors to order), but I can't see how to ask for an interceptor to be inside unknown interceptors. So, is there a spec'd way to do this? Or a JBoss way? View the original post : http://www.jboss.org/index.html?module=bb&op=viewtopic&p=4215723#... Reply to the post : http://www.jboss.org/index.html?module=bb&op=posting&mode=reply&a...