1:08 p.m.
hi,
I use eclipse and jboss 4.2.2.
I created a EAR project (enterprise application project) which contains 2 sub-projects :
an EJB project which contains some EJB and a JPA entity, and a java project which contains
the client "main" method.
here is my problem : nothing at the writing of the code, but an error at the deployment :
anonymous wrote : javax.persistence.PersistenceException:
org.hibernate.PersistentObjectException: detached entity passed to persist:
source_jpa.customer.Customer
| at
org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:629)
| at
org.hibernate.ejb.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:218)
| at
org.jboss.ejb3.entity.TransactionScopedEntityManager.persist(TransactionScopedEntityManager.java:182)
| at ejb.customer.CustomerBean.createCustomer(CustomerBean.java:45)
the createCustomer method is the following :
public Customer createCustomer(Customer customer, Address homeAddress) {
| if (customer==null)
| throw new ValidationException("customer object is null");
| customer.setHomeAddress(homeAddress);
| em.persist(customer);
|
| return customer;
I checked the mysql database, and the "t_customer" table exists but it is
empty.
for a better understanding, here is the JPA class:
package source_jpa.customer;
|
| import java.io.Serializable;
| import java.util.Calendar;
| import java.util.Date;
| import java.util.GregorianCalendar;
|
| import javax.persistence.CascadeType;
| import javax.persistence.Column;
| import javax.persistence.Entity;
| import javax.persistence.FetchType;
| import javax.persistence.GeneratedValue;
| import javax.persistence.GenerationType;
| import javax.persistence.Id;
| import javax.persistence.JoinColumn;
| import javax.persistence.OneToOne;
| import javax.persistence.PostLoad;
| import javax.persistence.PostPersist;
| import javax.persistence.PostUpdate;
| import javax.persistence.PrePersist;
| import javax.persistence.PreUpdate;
| import javax.persistence.Table;
| import javax.persistence.Temporal;
| import javax.persistence.TemporalType;
| import javax.persistence.Transient;
|
| import source_jpa.Address;
| import source_jpa.exception.ValidationException;
|
| //{|}
| @Entity
| @Table(name="t_customer")
| public class Customer implements Serializable{
|
| @Id
| @GeneratedValue(strategy=GenerationType.AUTO)
| private Long id;
|
| @Column(unique=true,nullable=false,length=8)
| private String login;
|
| @Column(nullable=false,length=8)
| private String password;
|
| @Column(nullable=false,length=30)
| private String firstname;
|
| @Column(nullable=false,length=30)
| private String lastname;
|
| private String telephone;
| private String email;
|
| @Column(name="date_of_birth")
| @Temporal(TemporalType.DATE)
| private Date dateOfBirth;
|
| @Transient
| private Integer age;
|
| @OneToOne(fetch=FetchType.EAGER,cascade=CascadeType.ALL)
| @JoinColumn(name="address_fk",nullable=true)
| private Address homeAddress;
|
| @PrePersist
| @PreUpdate
| private void validateData() throws ValidationException{
|
| if (firstname==null || firstname.equals(""))
| throw new ValidationException("Invalid first name");
| if (lastname==null || lastname.equals(""))
| throw new ValidationException("Invalid last name");
| if (login==null || login.equals(""))
| throw new ValidationException("Invalid login");
| if (password==null || password.equals(""))
| throw new ValidationException("Invalid password");
|
| }
|
| @PostLoad
| @PostPersist
| @PostUpdate
| public void calculateAge(){
|
| if (dateOfBirth==null){
| age=null;
| return;
| }
| Calendar birth=new GregorianCalendar();
| birth.setTime(dateOfBirth);
| Calendar now=new GregorianCalendar();
| now.setTime(new Date());
| int adjust=0;
| if (now.get(Calendar.DAY_OF_YEAR)-birth.get(Calendar.DAY_OF_YEAR)<0)
| adjust=-1;
| age=now.get(Calendar.YEAR)-birth.get(Calendar.YEAR)+adjust;
|
| }
can you help me?
olivier.
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