[jboss-jira] [JBoss JIRA] Resolved: (JBRULES-1040) Multi-pattern accumulate support
[ http://jira.jboss.com/jira/browse/JBRULES-1040?page=all ]
Edson Tirelli resolved JBRULES-1040.
------------------------------------
Fix Version/s: 4.0.2
(was: FUTURE)
Resolution: Done
Support for multi-pattern accumulate was added. Example:
Rule: Add to the Cheesery, all Cheese pieces whose type there are Persons who like it:
rule "MultiPatternAccumulate" salience 80
when
$cheesery : Cheesery( totalAmount > 30 )
from accumulate( $person : Person( $likes: likes) and $cheese
: Cheese( type == $likes ),
init( Cheesery cheesery = new Cheesery();
),
action( cheesery.addCheese( $cheese ); ),
reverse( cheesery.removeCheese( $cheese );
),
result( cheesery ) );
then
results.add( $cheesery );
end
All connectives used in the source must be explicitly defined, like the "and" in
the above example.
Support still needs to be added to the XML parser and documentation needs to be written.
Will open new tickets for these jobs.
Multi-pattern accumulate support
--------------------------------
Key: JBRULES-1040
URL: http://jira.jboss.com/jira/browse/JBRULES-1040
Project: JBoss Rules
Issue Type: Feature Request
Security Level: Public(Everyone can see)
Components: Reteoo, Drl Parser/Builder
Affects Versions: 4.0.0.GA
Reporter: Geoffrey De Smet
Assigned To: Edson Tirelli
Fix For: 4.0.2
[Edson said there might be already such an issue, but I couldn't find it looking
through jira.]
Something like this should be possible:
$multipleQueensHorizontal : Long()
from accumulate(
$q1 : Queen($id : id, $y : y);
Queen(id > $id, y == $y);
, count($q1)
);
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