Johannes Krämer [
http://community.jboss.org/people/johannesk] created the discussion
"How to recognize when async-node is finished?"
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http://community.jboss.org/message/548072#548072
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Hi,
I'm trying to run a test with a simple process definition that contains the start
state, an async node, a wait state and the end state. An example is attached.
I create a process instance, remember the ID, obtain the root token and send a signal. The
token then moves to the first node, which has set async to true. Then I save the
processInstance and close the JbpmContext so the job message is sent to the job executor.
The async node simply waits some time before it calls ExecutionContext.leaveNode() to send
the token into a wait state.
What I want to do now is: retrieve the process instance by the previously saved ID (with a
newly created JbpmContext), get the root token and send a signal to make it take the
transition to the end state.
My problem is: How long do I have to wait after the token was sent to the async node if I
want to be sure that the token has entered the next wait state and is no longer locked by
the job? Is there any possibility to be notified?
I tried to use a simple monitor where the main thread calls wait() after sending the first
signal and the node implementation calls notifyAll() after leaveNode(), but the token is
still locked by "Job(1)" when I send the second signal. It works if I wait some
extra time (e. g. 250 ms) in the main thread before sending the second signal, but that is
obviously not a good solution.
Kind regards
Johannes Krämer
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