Hello, I'm going through the hello world example from the seam book, and I'm getting an error I cannot resolve, that with an auto generated sql statement, that's not valid for postgres 8.1, the database I'm on. Here's my error: ...... 17:40:31,370 INFO [STDOUT] Hibernate: select next value for person_id_seq from dual_person_id_seq 17:40:31,394 WARN [JDBCExceptionReporter] SQL Error: 0, SQLState: 42601 17:40:31,394 ERROR [JDBCExceptionReporter] ERROR: syntax error at or near "value" 17:40:31,396 FATAL [application] javax.ejb.EJBException: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not get next sequence value javax.faces.el.EvaluationException: javax.ejb.EJBException: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not get next sequence value Here's the table definition - create table Person (id bigint not null, name varchar(255), primary key (id)) - create table dual_person_id_seq (zero integer) - create sequence person_id_seq start with 1 increment by 1 and here's the entity bean: @Entity @Name("person") @Table(name="person") @SequenceGenerator(name="person_sequence", sequenceName="person_id_seq") public class Person implements Serializable { private long id; private String name; @Id @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="person_sequence") public long getId() { return id;} public void setId(long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } } How do I get it to generate a valid sql statement for postgres? View the original post : http://www.jboss.com/index.html?module=bb&op=viewtopic&p=4117763#... Reply to the post : http://www.jboss.com/index.html?module=bb&op=posting&mode=reply&a...