Hi, Let?s say that I have outjected List variable | @Out | List<Person> employees; | Then through remoting I call changeList() method: | public void changeList(){ | | | employees = new ArrayList<Person>(); | Person person = new Person(); | person.setFirstName(?John?); | person.setLastName(?Smith?); | employess.add(person); | ?. | } | And now I don?t know how to update page that i.e. selectOneMenu shows list of employees with the employee who were added in changeList() method. Because after calling by ajax changeList() method the list (in selectOneMenu) on the page stays unchanged. Thanks for help in advance, jquery View the original post : http://www.jboss.com/index.html?module=bb&op=viewtopic&p=4085390#... Reply to the post : http://www.jboss.com/index.html?module=bb&op=posting&mode=reply&a...