Is it possible to insert more than one record in to database using the EntityHome object? I get following error, and not sure how to go around it. javax.persistence.PersistenceException: org.hibernate.HibernateException: identifier of an instance of au.edu.tisc.entity.OrgUserActivityLog was altered from 10001 to 10002 at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:629) at org.hibernate.ejb.AbstractEntityManagerImpl.flush(AbstractEntityManagerImpl.java:299) In my example, I am trying to insert user activity records in to the table during the authentication process called from Authenticator.authenticate. If I insert only one record it works ok; but if I try to insert another I get error on .persist() call. @Name("authenticator") public class Authenticator { public boolean authenticate() { @In(value = "activityLogger", required = false, create = true) private ActivityLogger activityLog; ... ... validate user details ... ... activityLog.log(...); <--insert first record - works ok ... ... activityLog.log(...); <--try to insert another - causes error ... } } @Name("activityLogger") public class ActivityLogger { public void log(OrgUser orgUser, String action) { OrgUserActivityLogHome orgUserActivityLogHome = (OrgUserActivityLogHome) Component.getInstance(OrgUserActivityLogHome.class, true); OrgUserActivityLog orgUserActivityLog = orgUserActivityLogHome.getInstance(); orgUserActivityLog.setId(KeyGenerator.getKey()); orgUserActivityLog.setAction(action); orgUserActivityLog.setOrganisationUser(orgUser); orgUserActivityLogHome.persist(); <-- Above error thrown here on 2nd insert. } } I am not sure why, error occurs on 2nd call; since first record insert had already called .persist() on the Entity Home object. View the original post : http://www.jboss.com/index.html?module=bb&op=viewtopic&p=4088693#... Reply to the post : http://www.jboss.com/index.html?module=bb&op=posting&mode=reply&a...