[jboss-user] [JBoss jBPM] - A question about jBPM process execution.

This is my code: | ProcessDefinition processDefinition = ProcessDefinition.parseXmlInputStream(new FileInputStream( | "jbpm/helloworld/processdefinition.xml")); | | ProcessInstance processInstance = new ProcessInstance(processDefinition); | | Token token = processInstance.getRootToken(); | | token.signal(); | System.out.println(token.getNode()); | | token.signal(); | System.out.println(token.getNode()); | This is the processdefinition.xml: <process-definition xmlns="" name="helloworld"> <start-state name="start"> </start-state> <end-state name="end"></end-state> </process-definition> My question is that why I need invoke signal two times. I assume that I only need to signal the first state and it will transition to the second state and then to the end state. The transition has been specified in the configuration file. View the original post : http://www.jboss.com/index.html?module=bb&op=viewtopic&p=4150360#... Reply to the post : http://www.jboss.com/index.html?module=bb&op=posting&mode=reply&a...