[rules-users] How to even out n buckets in Drools Planner?

I have n buckets and mn entities. Each bucket must have m entities. Each entity carries a weight. My objective is to even out the total weight per bucket, make them close to the average. For example, a solution like this is skewed, see their sums. bucket 1: 1,2,4,5=12 bucket 2: 6,8,9,6=29 bucket 3: 7,7,4,7=25 The same entities may be placed into buckets like this. This is more desirable as the sums are closer to the mean (and each other); one does not dominate the others. bucket 1: 1,8,7,4=20 bucket 2: 6,2,9,6=23 bucket 3: 7,7,5,4=23 *Question:*How do I write a rule for this: for each bucket, penalize (with soft scores) a bucket whose total entity.weight differs from the average total entity.weight of the buckets. Will I get the same results when I penalize each bucket for differing with *each other*? -- View this message in context: http://drools.46999.n3.nabble.com/How-to-even-out-n-buckets-in-Drools-Pla... Sent from the Drools: User forum mailing list archive at Nabble.com.