Hi Geoffrey, Wolfgang,
sure is the problem discretized (the layer on which it should be packed is
fixed size say 100cm x100cm and the rectangles have sizes to the cm) , that
was not the question.
I can build a planning value x/y with a list of 100 entries for every cm and
combine them, but i think this is very inefficent.
Yes, but I still believe in this approach.
The number of combinations is far less then any n^n formula where n is
the size of max double, float, long or integer.
Basically, this approach discretizes it, but not as handy.
I can´t imagine a solution where you can have multiple x-predecessors and
y-predecessors
and try to find out the combinations.
If i can´t use drools planner for the guilliotine based solution it´s ok,
then i will program it by hand in java.
But i found Drools very promising.
Greetings,
Ralph
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