Re: [rules-users] Test for element in an arraylist
You cannot use the operator "contains" in an eval(), where a simple
Java expression
must be written:
eval(odmList.contains($a1) && odmList.contains($a2))
But I agree with Jeremy: the original rule is rather unlikely, as it
would fire for
a single ODMAnswer being contained in the odmList, or two different ODMAnswers
being contained in the list, and then again for the same two ODMAnswers being
contained in the list...
Basics, study the basics...
-W
On 16 January 2013 18:03, Bojan Janisch
<bojan.janisch(a)scai.fraunhofer.de> wrote:
Nah thats not gonna work, because I'm using
an ArrayList as a global variable. I'm adding
and removing ODMAnswers in it and always want to
check if there are 2 ODMAnswers in it, to remove
them and generate a new one.
Of course I differ them in their properties, just
wanted to keep the problem simple and understandable.
Do you got another option than creating a local
$list variable?
----- Ursprüngliche Mail -----
Von: "Jeremy Ary" <jeremy.ary(a)gmail.com>
An: "Rules Users List" <rules-users(a)lists.jboss.org>
Gesendet: Mittwoch, 16. Januar 2013 17:54:32
Betreff: Re: [rules-users] Test for element in an arraylist
I should note that hopefully you can limit this to something like $list : ODAList ( ) (a
specific extends type of list where you could specify some criteria to be more specific
with) or can assure that you only have one List in play at that time, or you're going
to spend some execution going through every List in memory to check for these
occurrences.
Jeremy
On Wed, Jan 16, 2013 at 10:50 AM, Jeremy Ary < jeremy.ary(a)gmail.com > wrote:
Argh...Sorry, wrong key too early...here's the full changes:
rule "Combine ODMAnswers"
when
$list : List( )
$a1:ODMAnswer( some check ) from $list $a2:ODMAnswer( assuming something making this one
different than $a1 ) from $list
then
$list.add( new ODMAnswer( ) );
$list.remove($a1);
$list.remove($a2);
end
On Wed, Jan 16, 2013 at 10:47 AM, Jeremy Ary < jeremy.ary(a)gmail.com > wrote:
Try this;
rule "Combine ODMAnswers"
when
$a1:ODMAnswer( some check )
$a2:ODMAnswer( assuming something making this one different than $a1 )
eval(odmList contains $a1 && odmList contains $a2)
then
ODMAnswer answer = new ODMAnswer( );
odmList.add(answer);
odmList.remove($a1);
odmList.remove($a2);
end
On Wed, Jan 16, 2013 at 10:41 AM, Bojan Janisch < bojan.janisch(a)scai.fraunhofer.de
> wrote:
rule "Combine ODMAnswers"
when
$a1:ODMAnswer( )
$a2:ODMAnswer( )
eval(odmList contains $a1 && odmList contains $a2)
then
ODMAnswer answer = new ODMAnswer( );
odmList.add(answer);
odmList.remove($a1);
odmList.remove($a2);
end
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