Re: [rules-users] Optaplanner rule to assign employee only to shift when he/she has the skills

Thanks for the reply. It helped to see my mistake. I have now simplified the rule for testing purposes. I now have: rule "alternativeSkill" when $skill : Skill(code == '1') $employee : Employee() not SkillProficiency(employee == $employee, skill == $skill) then scoreHolder.addHardConstraintMatch(kcontext, -1);//scoreHolder.addSoftConstraintMatch(kcontext, - $contractLine.getWeight()); end I have three employees and 19 shifts. 1 employee has the necessary skills to do the shifts, the other 2 not. When I run the program I get: 14:42:19.237 [main] DEBUG o.o.c.i.l.DefaultLocalSearchSolverPhase - Step index (135), time spend (20000), score (-2hard/-182soft), best score (-2hard/-182soft), accepted/selected move count (85/252) for picked step (2013-12-09(Mon)_intake->evgey_Intaketeam(Evelien Geysen - Intaketeam) <=> 2013-12-05(Thu)_intake->mavan_Intaketeam(Marie Van de Vliet - Intaketeam)). 14:42:19.237 [main] INFO o.o.c.i.l.DefaultLocalSearchSolverPhase - Phase (1) localSearch ended: step total (136), time spend (20000), best score (-2hard/-182soft). 14:42:19.237 [main] INFO o.o.core.impl.solver.DefaultSolver - Solving ended: time spend (20000), best score (-2hard/-182soft), average calculate count per second (19839). I get 2 hard errors as expected. But the best solution still assigns all three employees to the shifts. Why do I not get a solution where only the one qualified employee is assigned to all shifts? That way I would get 0 hard errors. Am I missing something? -- View this message in context: http://drools.46999.n3.nabble.com/Optaplanner-rule-to-assign-employee-onl... Sent from the Drools: User forum mailing list archive at Nabble.com.