Re: [rules-users] Simple Disjunction Question

Thomas, I was curious about this and tried to set up a minimal sample, and as far as I can tell, this is not possible. Based on my testing, even if $a, $b, and $c ARE present, you cannot do this, because the evaluation short-circuits if $a is found, and therefore $b and $c are never defined. Even putting null-checks around the do($a) lines won't work, because the error happens before the RHS is evaluated. David Faulkner david.faulkner@ametnra.com<mailto:david.faulkner@ametnra.com> ________________________________ From: rules-users-bounces(a)lists.jboss.org [rules-users-bounces(a)lists.jboss.org] On Behalf Of thomas.polzin(a)gmail.com [thomas.polzin(a)gmail.com] Sent: Thursday, February 03, 2011 3:55 PM To: rules-users(a)lists.jboss.org Subject: [rules-users] Simple Disjunction Question Hi there Assume we have a rule like this: when $a : A(a==1) or ($b : B(b==1) and $c : C(c==1)) then do($a) do($b) do($c) end Assuming also, that for some reason I do not want to split this rule into two. Then, I get a NullPointer exception because either $a or $b and $c are not defined. Is there a way to catch or check for this. Thanks so much for any help Thomas