Re: [rules-users] [Planner]
Mats Norén wrote
Hi,
I've got a really simple problem that I can't seem to fix. :-)
I'm trying to use a simplified model for a room planning problem.
The planning entity is a Topic and the planning variables are Room and
TimeSlot.
A Person is tied to a Topic as a moderator.
Each Person can have multiple Topics as an interest.
The hard constraints are that a Person cannot be moderator in two Topics
at
the same TimeSlot and that there cannot be multiple Topics in the same
Room
at the same TimeSlot.
rule "conflictingModeratorInSameTimeslot"
when
$leftTopic : Topic($leftId : id, $leftTimeslot : timeSlot,
timeSlot
!= null, $leftModerator: moderator)
$rightTopic : Topic(timeSlot == $leftTimeslot, moderator ==
$leftModerator, id > $leftId)
then
scoreHolder.addHardConstraintMatch(kcontext, -1);
end
rule "multipleTopicsInSameRoomAndTimeslot"
when
$leftTopic : Topic($leftId : id, $leftTimeslot : timeSlot,
timeSlot
!= null, $leftRoom: room)
$rightTopic : Topic(timeSlot == $leftTimeslot, room == $leftRoom,
id > $leftId)
then
scoreHolder.addHardConstraintMatch(kcontext, -1);
end
yep, that's like in the curriculum course scheduling example
Mats Norén wrote
The soft constraint that I have a problem with is that a Person has
multiple Topics as interests and I would like to penalize the Solution
with
the number of Topics in the Persons interests collection with the number
of
Topics that are allocated at the same TimeSlot.
Any ideas on how to go about this?
when
$p : Person
$rightTopic : Topic( $leftId : id, $t : timelsot)
exists Interest(person == $p, topic == $leftTopic)
Topic(id > $leftId, timeslot == $t)
exists Interest(person == $p, topic == $rightTopic)
then
// This will count the number of conflicting topic pairs
// 2 conflicting topics count 1
// 3 conflicting topics count 3
// 4 conflicting topics count 6
You 'll probably want to split up the class Topic into Topic and
TopicAssignement, like in the examination example (see domain diagram in
latest manual)
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