Each (not *the*) Recommendation with the maximum recommValue can be found
using
$recMax: Recommendation( slot == 1, $recommValue: recommValue)
not Recommendation( slot == 1, recommValue > $recommValue )
with $recMax being bound to one of the Recommendations with the maximum,
and the maximum value being bound to $recommValue.
-W
On 24 November 2012 13:18, raffi <christian.koehler(a)s2008.tu-chemnitz.de>wrote:
Hello,
I have a problem with using the /from accumulate/ statement. It is because
I'd like to optmize my code a liitle bit. There are two rules that I like
to
merge.
/query "max recomm value for slot 1"
accumulate (Recommendation(slot == 1, $recomm_value : recommValue),
max : max($recomm_value))
end/
and
/query "recomms for slot 1"
recomm : Recommendation(slot == 1)
end/
So with the first rule I get the maximum of the variable recommValue. The
second rule is for searching exactly this Recommendation-fact with this
value. Now I tried to merge them in the following way:
/
query "recomm for slot 1"
$recomm : Recommendation() from
accumulate(Recommendation(
slot == 1, $recomm_value :
recommValue),
max($recomm_value)
)
end/
But the returned value always is a double one. Is it because of the usage
of
the maximum function? Is it possible to solve this problem with only one
query (getting that Recommendation-fact with the highest recommValue)?
Regards...
--
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