Teresa,
I made a code change in Hibernate 4.x that impacts
serialization/deserialization of EntityManagerFactories. My code change
helps Hibernate to work correctly in clustered environments (HHH-6897)
but it looks like my change also broke your application. In a clustered
environment, each entity manager factory will have a unique name.
In your application, could you try setting
"hibernate.ejb.entitymanager_factory_name" to a unique name? Perhaps
you could try setting it to:
"newt" + username
Scott
On 01/08/2013 08:03 AM, Teresa Batista Neto wrote:
Hello,
I just copy/past the exception call stack from when the "registry
contains more than one" error is thrown. The link is:
http://pastie.org/private/cmmoyaouedgrbgpat88fxw <
http://pastie.org/5647726>
Thanks in advance,
Teresa
On Thu, Dec 20, 2012 at 3:38 PM, Scott Marlow <smarlow(a)redhat.com
<mailto:smarlow@redhat.com>> wrote:
I would like to see the exception call stack from when the "registry
contains more than one" error is thrown. You can copy it to a
website like
pastie.org <
http://pastie.org> or
pastebin.com
<
http://pastebin.com> and paste the link here.
Scott
On 12/20/2012 05:38 AM, Teresa Batista Neto wrote:
Dear all,
After upgrading JPA from 3.6.1 to 4.1.8 I start getting the
following error:
"Error: registry contains more than one (2) entity manager
factories:
PERSISTENCE_UNIT_NAME"
Below you can find a brief summary of our specification
requirements.
- User logins in the web application using their own oracle database
account.
- The web application only needs to access one database schema;
- The access rights are managed using oracle roles and grant
privilegies.
- Only one database schema and multiple user oracle accounts.
- We only set the username and password when users tries to
login in the
web application.
- The EntityManagerFactory is created using the username and
password of
the user.
- Because our web application only access one database we only
use one
persistence unit name.
E.g. persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
xmlns="http://java.sun.com/__xml/ns/persistence
<
http://java.sun.com/xml/ns/persistence>"
xmlns:xsi="http://www.w3.org/__2001/XMLSchema-instance
<
http://www.w3.org/2001/XMLSchema-instance>"
xsi:schemaLocation="http://__java.sun.com/xml/ns/__persistence
<
http://java.sun.com/xml/ns/persistence>
http://java.sun.com/xml/ns/__persistence/persistence_1_0.__xsd
<
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd>">
<persistence-unit name="PERSISTENCE_UNIT_NAME">
<provider>org.hibernate.ejb.__HibernatePersistence</__provider>
<properties>
<property name="hibernate.connection.__driver_class"
value="oracle.jdbc.
OracleDriver">
<property name="hibernate.connection.__url"
value="jdbc:oracle:xx...">
<property name="hibernate.dialect"
value="org.hibernate.dialect.
Oracle10gDialect">
<property name="hibernate.default___schema"
value="SCHEMA_NAME">
<property name="hibernate.connection.__username"
value="USERNAME">
<property name="hibernate.connection.__password"
value="PASSWORD">
<property name="hibernate.connection.__autocommit"
value="false">
<property name="hbm2ddl.auto" value="validate">
<property name="hibernate.show_sql"
value="true">
<property name="hibernate.format_sql"
value="true">
</properties>
</persistence-unit>
</persistence>
E.g. how we create and close the entity manager factory
Map<String, String> configuration = new ProviderConfiguration();
configuration.put("hibernate.__connection.username", username);
configuration.put("hibernate.__connection.password", password);
EntityManagerFactory emf =
Persistence.__createEntityManagerFactory("__PERSISTENCE_UNIT_NAME",
configuration);
EntityManager em = emf.createEntityManager();
SptrTaxNode t = em.find(SptrTaxNode.class, 9606);
em.close();
emf.close();
Does anyone ever had a similar situation? Any ideas on how can I
solve this
problem?
Thanks in advance,
Teresa
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