Re: [hibernate-dev] Insert not working

Hi, I have just started working on hibernate. I was trying to start with some sample applications. I am facing this problem when I am trying to insert data. It does not throw any error but does not do any insert. I can easily fetch information using the same mapping. Can someone help me with this. I am using MYSQL5 with hibernate 3 My hibernate-cfg.xml loooks like following <?xml version='1.0' encoding='utf-8'?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <property name="hibernate.connection.driver_class"> com.mysql.jdbc.Driver</property> <property name="hibernate.connection.url ">jdbc:mysql://localhost/test</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.connection.password"></property> <property name="hibernate.connection.pool_size">10</property> <property name="show_sql">true</property> <property name="dialect">org.hibernate.dialect.MySQLDialect</property> <!-- Mapping files --> <mapping resource="contact.hbm.xml"/> </session-factory> </hibernate-configuration> my contact.hbm.xml looks like <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping> <class name="com.test.dbo.contact" table="contacts"> <id name="id" type="long" column="id" > <generator class="increment"/> </id> <property name="email"> <column name="email" /> </property> <property name="modified_date"> <column name="modified_date"/> </property> </class> </hibernate-mapping> The Java Code looks like the following SessionFactory factory = null; try { Configuration cfg = new Configuration(); factory = cfg.configure().buildSessionFactory(); Session session = factory.openSession(); notification_email ne = createNotificationEmail(); session.save(ne); session.flush(); session.close(); } catch(Exception e) { System.out.println(""+e); e.printStackTrace(); } I will greatly appreciate if someone can provide me an answer. Really struggling. thanks