Hi,
But I don't like to use startProcess several times.
I shouldn't invoke startprocess every time when i add another process.
I have ruleFlow files as input and i want to invoke startProcess one time.
I don't like to pass id by explicit form.
I need a generic code for this.
Thanks
Kris Verlaenen wrote:
Each process defines its own id. If you look in the xml, the process
element has an id attribute. In the editor, click on the background of
your process and you will also see the id property in the properties view.
So you should give each of your processes a new id. Then you can easily
start each of those processes:
startProcess("MyFirstProcess");
startProcess("MySecondProcess");
Does that make sense?
Kris
Quoting mjido <m.benlachgar(a)netfective.ma>:
>
> Hello,
> I think i'm not very clear.
> I have multiple ruleFlow files and i want to execute them with
> startProcess(id).
> But how i can associate each ruleFlow with his id.
> Is there a way to get id process from ruleFlow file?
>
> mjido wrote:
> >
> > Hi,
> > I use workingMemory.startProcess(Id_process) to execute multiple
> rulflow
> > files.
> > So i want to pass Id_proccess as a dynamic value.
> > Is there any way to make this?
> > Any helps will be very appreciated.
> >
>
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