jboss-development July 2006

That seems a bit whacked. There is no way to do this via reflection that I know of. The only way you will be able to do it is to wrap the object in a proxy and generate a method that uses the invokespecial bytecode op to call the super class method. This is what is generated when a method invokes super.method. The superTestDisplay() method in this version of A just calls super.testDisplay(): public class lang.reflect.A extends lang.reflect.SuperA{ public lang.reflect.A(); Code: 0: aload_0 1: invokespecial #1; //Method lang/reflect/SuperA."<init>":()V 4: return public void testDisplay(); Code: 0: getstatic #2; //Field java/lang/System.out:Ljava/io/PrintStream; 3: ldc #3; //String A.testDisplay() 5: invokevirtual #4; //Method java/io/PrintStream.println:(Ljava/lang/Str ing;)V 8: return public void superTestDisplay(); Code: 0: aload_0 1: invokespecial #5; //Method lang/reflect/SuperA.testDisplay:()V 4: return } -----Original Message----- From: jboss-development-bounces(a)lists.jboss.org [mailto:jboss-development-bounces@lists.jboss.org] On Behalf Of Emmanuel Bernard Sent: Wednesday, July 26, 2006 2:52 PM To: JBoss.org development list Subject: Re: [JBoss-dev] calling a super method implementation The reasoning behind that is the EJB3 spec A class is permitted to override an inherited callback method of the same callback type, and in this case, the overridden method is not invoked. Note that if *a method overrides an inherited callback method* but specifies a different lifecycle event or *is not a lifecycle callback method* (ie not annotated), *the overridden method will be invoked*. Emmanuel Bernard wrote: > > > I don't know how to (or if it's even possible to) call by reflection a > super implementation of a given method > > public class SuperA { > public void testDisplay() { > System.out.println("SuperA"); > } > } > > public class A extends SuperA { > public void testDisplay() { > System.out.println("A"); > } > } > > SuperA.class.getDeclaredMethod("testDisplay", new Class[] > {}).invoke(aInstance, new Object[] {}); > will actually display 'A' > > I'd like to display 'SuperA' > > Any help apreciated > > > _______________________________________________ > jboss-development mailing list > jboss-development(a)lists.jboss.org > https://lists.jboss.org/mailman/listinfo/jboss-development > _______________________________________________ jboss-development mailing list jboss-development(a)lists.jboss.org https://lists.jboss.org/mailman/listinfo/jboss-development

18 years, 5 months

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calling a super method implementation

by Emmanuel Bernard

I don't know how to (or if it's even possible to) call by reflection a super implementation of a given method public class SuperA { public void testDisplay() { System.out.println("SuperA"); } } public class A extends SuperA { public void testDisplay() { System.out.println("A"); } } SuperA.class.getDeclaredMethod("testDisplay", new Class[] {}).invoke(aInstance, new Object[] {}); will actually display 'A' I'd like to display 'SuperA' Any help apreciated

18 years, 5 months

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ejb3-4.0-testsuite Build Completed With Testsuite Errors

by qa＠jboss.com

18 years, 5 months

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jboss-remoting-testsuite-1.5 Build Completed With Testsuite Errors

by qa＠jboss.com

18 years, 5 months

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by qa＠jboss.com

18 years, 5 months

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jboss-3.2-testsuite Build Completed With Testsuite Errors

by qa＠jboss.com

18 years, 5 months

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jboss-development July 2006